Five particles of mass 2 kg are attached to the rim of a circular disc of radius 0.1 m and negligible mass. Moment of inertia of the system about the axis passing through the centre of the disc and perpendicular to its plane is:

Question

Five particles of mass 2 kg are attached to the rim of a circular disc of radius 0.1 m and negligible mass. Moment of inertia of the system about the axis passing through the centre of the disc and perpendicular to its plane is: (A)  1 kg m2  (B)  0.1 kg m2  (C)  2 kg m2  (D)  0.2 kg m2

Tardigrade Admin · Accepted Answer

The moment of inertia of the given system that contains

5

particles each of mass

= 2 k g

on the rim of circular disc of radius

0.1 m

and of negligible mass is given by

= M I

of disc

+ M I

of particle
Since the mass of the disc is negligible therefore,

M I

of the system

= M I

of particle

= 5 \times 2 \times (0.1)^{2} = 0.1 k g m^{2}

Q. Five particles of mass $2 k g$ are attached to the rim of a circular disc of radius $0.1 m$ and negligible mass. Moment of inertia of the system about the axis passing through the centre of the disc and perpendicular to its plane is:

$1 k g m^{2}$

$0.1 k g m^{2}$

$2 k g m^{2}$

$0.2 k g m^{2}$

Q. Five particles of mass 2kg are attached to the rim of a circular disc of radius 0.1m and negligible mass. Moment of inertia of the system about the axis passing through the centre of the disc and perpendicular to its plane is:

1kgm2

0.1kgm2

2kgm2

0.2kgm2

The moment of inertia of the given system that contains 5 particles each of mass =2kg on the rim of circular disc of radius 0.1m and of negligible mass is given by =MI of disc +MI of particle Since the mass of the disc is negligible therefore, MI of the system =MI of particle =5×2×(0.1)2=0.1kgm2

Q. Five particles of mass $2 k g$ are attached to the rim of a circular disc of radius $0.1 m$ and negligible mass. Moment of inertia of the system about the axis passing through the centre of the disc and perpendicular to its plane is:

$1 k g m^{2}$

$0.1 k g m^{2}$

$2 k g m^{2}$

$0.2 k g m^{2}$