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  4. Five particles of mass 2 kg are attached to the rim of a circular disc of radius 0.1 m and negligible mass. Moment of inertia of the system about the axis passing through the centre of the disc and perpendicular to its plane is:

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Q. Five particles of mass $2\,kg$ are attached to the rim of a circular disc of radius $0.1\,m$ and negligible mass. Moment of inertia of the system about the axis passing through the centre of the disc and perpendicular to its plane is:

JIPMERJIPMER 2005System of Particles and Rotational Motion

Solution:

The moment of inertia of the given system that contains $5$ particles each of mass $=2\, kg$ on the rim of circular disc of radius $0.1 m$ and of negligible mass is given by
$= MI$ of disc $+ MI$ of particle
Since the mass of the disc is negligible therefore, $MI$ of the system $= MI $ of particle
$=5 \times 2 \times(0.1)^{2}=0.1 \,kg \,m ^{2}$