Five capacitors each of 10 μ F capacity are connected to a potential of 100 V as shown in figure. The equivalent capacitance beween the points A and B is:

Question

Five capacitors each of 10 μ F capacity are connected to a potential of 100 V as shown in figure. The equivalent capacitance beween the points A and B is: (A) 5 μ F  (B) 10 μ F  (C) 15 μ F  (D) 20 μ F

Tardigrade Admin · Accepted Answer

Since, the ratio of capacitances in opposite arms of bridge is same, hence it is a balanced Wheatstone bridge. Therefore, capacitance of arm CD becomes ineffective. The circuit now reduces, to consisting of two sets of series capacitors. Hence, resultant capacitance is 10 μ F .

Q. Five capacitors each of $10 μ F$ capacity are connected to a potential of $100 V$ as shown in figure. The equivalent capacitance beween the points $A$ and $B$ is:

$5 μ F$

$10 μ F$

$15 μ F$

$20 μ F$

Since, the ratio of capacitances in opposite arms of bridge is same, hence it is a balanced Wheatstone bridge. Therefore, capacitance of arm $C D$ becomes ineffective. The circuit now reduces, to consisting of two sets of series capacitors. Hence, resultant capacitance is $10 μ F$ .

Q. Five capacitors each of 10μF capacity are connected to a potential of 100V as shown in figure. The equivalent capacitance beween the points A and B is:

5μF

10μF

15μF

20μF