Question

Five capacitors are connected as shown in the figure. The equivalent capacitance between $A$ and $B$ is :

• A. $4\mu F$
• B. $3\mu F$
• C. $2\mu F$
• D. $1\mu F$

Answer 1

Answer: (C)

Equivalent capacitance of $2\mu F$ and $2\mu F$ connected in series is given by $=\frac{2\times 2}{2+2}=1\mu F$
Now, equivalent capacitance ot $1\mu F$ and $1\mu F$ connected in parallel is $=1+1=2\mu F$ equivalent circuit
Now $2\mu F$ and $2\mu F$ are in connected in series $=\frac{2\times 2}{2+2}=1\mu F$
Equivalent capacitance between $A$ and $B$ is given by,
$C=1+1=2\mu F$