Q.
Five capacitors are connected as shown in the figure. The equivalent capacitance between $A$ and $B$ is :
Haryana PMTHaryana PMT 2001
Solution:
Equivalent capacitance of $2 \,\mu F$ and $2 \,\mu F$ connected in series is given by $=\frac{2 \times 2}{2+2}=1\, \mu F$
Now, equivalent capacitance ot $1 \,\mu F$ and $1 \,\mu F$ connected in parallel is $=1+1=2\, \mu F$ equivalent circuit
Now $2 \,\mu F$ and $2 \,\mu F$ are in connected in series $=\frac{2 \times 2}{2+2}=1\, \mu F$
Equivalent capacitance between $A$ and $B$ is given by,
$C=1+1=2\, \mu F$


