First three nearest neighbour distances for simple cubic lattice are respectively (edge length of unit cell = a):

Question

First three nearest neighbour distances for simple cubic lattice are respectively (edge length of unit cell = a): (A) a, √2 a, √3 a (B) √3 a, √2 a, a (C) a, √2 a, 2 a (D) a, √3 a, 2 a

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<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/4de749f57469418d0fb7dc2cc7e3a34d-.png" /> AB = a (1 st . nearest ) AC =√2 a (2 nd . nearest ) AH =√3 a (3 rd . nearest )

Q. First three nearest neighbour distances for simple cubic lattice are respectively (edge length of unit cell $=$ a):

$a, 2 a, 3 a$

$3 a, 2 a, a$

$a, 2 a, 2 a$

$a, 3 a, 2 a$

$A B = a (1^{s t}$ nearest $)$

$A C = 2 a (2^{n d}$ nearest $)$

$A H = 3 a (3^{r d}$ nearest $)$

Q. First three nearest neighbour distances for simple cubic lattice are respectively (edge length of unit cell = a):

a,2​a,3​a

3​a,2​a,a

a,2​a,2a

a,3​a,2a