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Q. First three nearest neighbour distances for simple cubic lattice are respectively (edge length of unit cell $=$ a):

The Solid State

Solution:

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$AB = a \left(1^{ st }\right.$ nearest $)$

$AC =\sqrt{2} a \left(2^{ nd }\right.$ nearest $)$

$AH =\sqrt{3} a \left(3^{ rd }\right.$ nearest $)$