Find the value of the potential at x=+x , if a uniform electric field having a magnitude E0 and directed along the positive x- axis exists. Take the potential as zero at x=0 .

Question

Find the value of the potential at x=+x , if a uniform electric field having a magnitude E0 and directed along the positive x- axis exists. Take the potential as zero at x=0 . (A) V(x)=+x( E)0 (B) V(x)=-x( E)0 (C) V(x)=+x2( E)0 (D) V(x)=-x2( E)0

Tardigrade Admin · Accepted Answer

As E=-(d V/d r) ∴ +E0=-([V (x) - 0]/x) or Vx=-E0x

Q. Find the value of the potential at $x = + x$ , if a uniform electric field having a magnitude $E_{0}$ and directed along the positive $x -$ axis exists. Take the potential as zero at $x = 0$ .

$V (x) = + x (E)_{0}$

$V (x) = - x (E)_{0}$

$V (x) = + x^{2} (E)_{0}$

$V (x) = - x^{2} (E)_{0}$

As $E = - \frac{d V}{d r}$
$∴ + E_{0} = - \frac{[ V ( x ) - 0 ]}{x}$
or $V_{x} = - E_{0} x$

Q. Find the value of the potential at x=+x , if a uniform electric field having a magnitude E0​ and directed along the positive x− axis exists. Take the potential as zero at x=0 .

V(x)=+x(E)0​

V(x)=−x(E)0​

V(x)=+x2(E)0​

V(x)=−x2(E)0​