Find the root mean square voltage for the variation of voltage as shown in the adjacent figure

Question

Find the root mean square voltage for the variation of voltage as shown in the adjacent figure <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-kowv7w6fayv7adah.jpg" /> (A) V0√(7/12) (B) V0√(1/3) (C) (3 V0/4) (D) V0√(7/24)

Tardigrade Admin · Accepted Answer

Vrms=√(∫ limits 01 V02 t2 dt + ∫ limits 12 ((V0/2))2 dt/2)=V0√(7/24)

Q. Find the root mean square voltage for the variation of voltage as shown in the adjacent figure

$V_{0} \frac{7}{12}$

$V_{0} \frac{1}{3}$

$\frac{3 V _{0}}{4}$

$V_{0} \frac{7}{24}$

$V_{r m s} = \frac{0 \int 1 V _{0}^{2} t ^{2} d t + 1 \int 2 ( \frac{V _{0}}{2} ) ^{2} d t}{2} = V_{0} \frac{7}{24}$

Q. Find the root mean square voltage for the variation of voltage as shown in the adjacent figure

V0​127​​

V0​31​​

43V0​​

V0​247​​

Vrms​=20∫1​V02​t2dt+1∫2​(2V0​​)2dt​​=V0​247​​

$V_{0} \frac{7}{12}$

$V_{0} \frac{1}{3}$

$\frac{3 V _{0}}{4}$

$V_{0} \frac{7}{24}$

$V_{r m s} = \frac{0 \int 1 V _{0}^{2} t ^{2} d t + 1 \int 2 ( \frac{V _{0}}{2} ) ^{2} d t}{2} = V_{0} \frac{7}{24}$