Find the refractive index of the material of the prism, if the angle of minimum deviation from the prism is 37° and angle of prism is 53° [take sin 26.5°=1 / 2.234 ]

Question

Find the refractive index of the material of the prism, if the angle of minimum deviation from the prism is 37° and angle of prism is 53° [take sin 26.5°=1 / 2.234 ] (A) 1.58 (B) 1.99 (C) 2.88 (D) 3.1

Tardigrade Admin · Accepted Answer

μ=( sin ((A+δm/2))/ sin ( A / 2))=( sin 45°/ sin 26.5°) =1.58

Q. Find the refractive index of the material of the prism, if the angle of minimum deviation from the prism is $3 7^{\circ}$ and angle of prism is $5 3^{\circ}$ [take $sin 26. 5^{\circ} = 1/2.234$ ]

$1.58$

$1.99$

$2.88$

$3.1$

$μ = \frac{s i n ( \frac{A + δ _{m}}{2} )}{s i n ( A /2 )} = \frac{s i n 4 5 ^{\circ}}{s i n 26. 5 ^{\circ}}$
$= 1.58$

Q. Find the refractive index of the material of the prism, if the angle of minimum deviation from the prism is 37∘ and angle of prism is 53∘ [take sin26.5∘=1/2.234 ]

1.58

1.99

2.88

3.1