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Q. Find the refractive index of the material of the prism, if the angle of minimum deviation from the prism is $37^{\circ}$ and angle of prism is $53^{\circ}$ [take $\sin 26.5^{\circ}=1 / 2.234$ ]

Ray Optics and Optical Instruments

Solution:

$\mu=\frac{\sin \left(\frac{A+\delta_m}{2}\right)}{\sin ( A / 2)}=\frac{\sin 45^{\circ}}{\sin 26.5^{\circ}} $
$=1.58$