Find the power of the circuit in steady state.

Question

Find the power of the circuit in steady state. (A) 1.5 W (B) 2 W (C) 1 W (D) None of these

Tardigrade Admin · Accepted Answer

In steady state, the branch containing capacitors ca be neglected. So, reduced circuit is as follows: <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/1c7ba263870910307643cd76f089df15-.png" /> Power, P=(V2/R)=((2)2/4)=1 W

Q. Find the power of the circuit in steady state.

1.5 W

2 W

1 W

None of these

In steady state, the branch containing capacitors ca be neglected. So, reduced circuit is as follows:

Power, $P = \frac{V ^{2}}{R} = \frac{( 2 ) ^{2}}{4} = 1 W$

Q. Find the power of the circuit in steady state.

1.5 W

2 W

1 W

None of these

In steady state, the branch containing capacitors ca be neglected. So, reduced circuit is as follows: Power, P=RV2​=4(2)2​=1W

In steady state, the branch containing capacitors ca be neglected. So, reduced circuit is as follows:

Power, $P = \frac{V ^{2}}{R} = \frac{( 2 ) ^{2}}{4} = 1 W$