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  4. Find the power of the circuit in steady state.

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Q. Find the power of the circuit in steady state.Physics Question Image

Current Electricity

Solution:

In steady state, the branch containing capacitors ca be neglected. So, reduced circuit is as follows:
image
Power, $P=\frac{V^{2}}{R}=\frac{(2)^{2}}{4}=1 W$