Question

Find the polarisation angle if its critical angle for a transparent crystal-air medium is $60^{\circ }$ .

• A. ${\cot }^{-1}(2)$
• B. ${\cot }^{-1}\left(\frac{1}{2}\right)$
• C. ${\tan }^{-1}\left(\frac{2}{\sqrt{3}}\right)$
• D. ${\tan }^{-1}\left(\frac{\sqrt{3}}{2}\right)$

Answer 1

Answer: (C)

$\sin C=\frac{1}{\mu }$
$\mu =\frac{1}{\sin 60^{\circ }}$
$H=\left(\frac{2}{\sqrt{3}}\right)$
$l_p={\tan }^{-1}(\mu )$
$I_p={\tan }^{-1}\left(\frac{2}{\sqrt{3}}\right)$