Question

Find the polarisation angle if its critical angle for a transparent crystal-air medium is $60^\circ $ .

• A. $\cot ^{-1}(2)$
• B. $\cot ^{-1}\left(\frac{1}{2}\right)$
• C. $\tan ^{-1}\left(\frac{2}{\sqrt{3}}\right)$
• D. $\tan ^{-1}\left(\frac{\sqrt{3}}{2}\right)$

Answer 1

Answer: (C)

$\sin C=\frac{1}{\mu}$
$\mu=\frac{1}{\sin 60^{\circ}}$
$H=\left(\frac{2}{\sqrt{3}}\right)$
$l_p=\tan ^{-1}(\mu)$
$I_p=\tan ^{-1}\left(\frac{2}{\sqrt{3}}\right)$