Find the number of stereoisomers of 1,2-dihydroxy cyclopentane.

Question

Find the number of stereoisomers of 1,2-dihydroxy cyclopentane. (A) 1 (B) 2 (C) 3 (D) 4

Tardigrade Admin · Accepted Answer

Symmetrical molecule <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/dea08f2588e2b0a61efd327f84f77b30-.png" /> Number of chiral carbon atoms = 2 (even) Number of stereoisomers = 2n-1+2(n/2)-1 =22-1+2(2/2)-1=21+20=2+1=3

Q. Find the number of stereoisomers of 1,2-dihydroxy cyclopentane.

1

2

3

4

Symmetrical molecule

Number of chiral carbon atoms = 2 (even)

Number of stereoisomers = $2^{n - 1} + 2^{\frac{n}{2} - 1}$

$= 2^{2 - 1} + 2^{\frac{2}{2} - 1} = 2^{1} + 2^{0} = 2 + 1 = 3$

Q. Find the number of stereoisomers of 1,2-dihydroxy cyclopentane.

1

2

3

4

Symmetrical molecule Number of chiral carbon atoms = 2 (even) Number of stereoisomers = 2n−1+22n​−1 =22−1+222​−1=21+20=2+1=3

Symmetrical molecule

Number of chiral carbon atoms = 2 (even)

Number of stereoisomers = $2^{n - 1} + 2^{\frac{n}{2} - 1}$

$= 2^{2 - 1} + 2^{\frac{2}{2} - 1} = 2^{1} + 2^{0} = 2 + 1 = 3$