Find the magnetic field at point P due to a straight line segment AB of length 6 cm carrying a current of 5 A. (See figure) (μ0 = 4π × 10-7 N-A-2)

Question

Find the magnetic field at point P due to a straight line segment AB of length 6 cm carrying a current of 5 A. (See figure) (μ0 = 4π × 10-7 N-A-2) (A) 3.0 × 10-5 T (B) 2.5 × 10-5 T (C) 2.0 × 10-5 T (D) 1.5 × 10-5 T

Tardigrade Admin · Accepted Answer

b = (μ0 I/4 π d) 2 sin θ d = 4 cm sin θ = (3/5)

Q. Find the magnetic field at point $P$ due to a straight line segment $A B$ of length $6 c m$ carrying a current of $5 A$ . (See figure) ( $μ_{0} = 4 π \times 1 0^{- 7} N - A^{- 2})$

$3.0 \times 1 0^{- 5} T$

$2.5 \times 1 0^{- 5} T$

$2.0 \times 1 0^{- 5} T$

$1.5 \times 1 0^{- 5} T$

$b = \frac{μ _{0} I}{4 π d} 2 s in θ$
d = 4 cm
$s in θ = \frac{3}{5}$

Q. Find the magnetic field at point P due to a straight line segment AB of length 6cm carrying a current of 5A. (See figure) (μ0​=4π×10−7N−A−2)

3.0×10−5T

2.5×10−5T

2.0×10−5T

1.5×10−5T