Question

Find the magnetic field at point $P$ due to a straight line segment $AB$ of length $6\, cm$ carrying a current of $5\, A$. (See figure) ($\mu_0 \, = \, 4\pi \times \, 10^{-7} \, N-A^{-2})$

• A. $3.0 \times 10^{-5} T$
• B. $2.5 \times 10^{-5} T$
• C. $2.0 \times 10^{-5} T$
• D. $1.5 \times 10^{-5} T$

Answer 1

Answer: (D)

$b \, = \, \frac{\mu_0 I}{4 \pi d} \, 2 sin \theta$
d = 4 cm
$sin \theta \, = \, \frac{3}{5}$