Question

Find the length of the arc of a sector of a circle whose angle at the centre is $120^{\circ }$ and area of the sector is $462c{m}^2$.
The following are the steps involved in solving the above problem. Arrange them in sequential order.
(A) Given, $\theta =120^{\circ }$, area of the sector $=462c{m}^2$. We know that $A=\frac{\theta }{360^{\circ }}\times \pi r^2$.
(B) $\Rightarrow 462=\frac{120^{\circ }}{360^{\circ }}\times \frac{22}{7}(r{)}^2\Rightarrow r=21cm$.
(C) Length of the arc of the sector $=\frac{\theta }{360^{\circ }}\times 2\pi r$ $=\frac{120^{\circ }}{360^{\circ }}\times 2\times \frac{22}{7}\times 21$.
(D) $\therefore$ Length of the arc $=44cm$

• A. ABCD
• B. ACBD
• C. BACD
• D. BCAD

Answer 1

Answer: (A)

$ABCD$ is the required sequential order.