1. Tardigrade
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  4. Find the length of the arc of a sector of a circle whose angle at the centre is 120° and area of the sector is 462 cm 2. The following are the steps involved in solving the above problem. Arrange them in sequential order. (A) Given, θ=120°, area of the sector =462 cm 2. We know that A=(θ/360°) × π r2. (B) ⇒ 462=(120°/360°) × (22/7)(r)2 ⇒ r=21 cm. (C) Length of the arc of the sector =(θ/360°) × 2 π r =(120°/360°) × 2 × (22/7) × 21. (D) ∴ Length of the arc =44 cm

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Q. Find the length of the arc of a sector of a circle whose angle at the centre is $120^{\circ}$ and area of the sector is $462 cm ^2$.
The following are the steps involved in solving the above problem. Arrange them in sequential order.
(A) Given, $\theta=120^{\circ}$, area of the sector $=462 cm ^2$. We know that $A=\frac{\theta}{360^{\circ}} \times \pi r^2$.
(B) $\Rightarrow 462=\frac{120^{\circ}}{360^{\circ}} \times \frac{22}{7}(r)^2 \Rightarrow r=21 cm$.
(C) Length of the arc of the sector $=\frac{\theta}{360^{\circ}} \times 2 \pi r$ $=\frac{120^{\circ}}{360^{\circ}} \times 2 \times \frac{22}{7} \times 21$.
(D) $\therefore$ Length of the arc $=44 cm$

Mensuration

Solution:

$ABCD$ is the required sequential order.