Question

Find the charge (in $\mu C$ ) on the capacitor of value $2\mu F$ in the figure shown at steady state.

Answer 1

Answer: 5

Using cell equivalent method for two independent circuits, We get the following equivalent circuit:

Since in steady state there is no current flow, the all resistors are of no use. So charge on both the capacitors will be $q=\frac{3}{2}(5)=\frac{15}{2}\mu C$
Now, charge on $2\mu F$ capacitor will be
$q_2=\frac{15}{2}\times \frac{2}{3}=5\mu C$