Find the average molar mass of a gaseous mixture in g / mole , which contains 1.2046 × 1023 atoms of an unknown gas and 0.2 mole of H, gas. The weight of mixture is 22 g.

Question

Find the average molar mass of a gaseous mixture in g / mole , which contains 1.2046 × 1023 atoms of an unknown gas and 0.2 mole of H, gas. The weight of mixture is 22 g. (A) 44 (B) 55 (C) 110 (D) 22

Tardigrade Admin · Accepted Answer

Average molar mass =( text Total weight / text Total moles ) (22/(1.2046 × 1023)6.023 × 1023)+0.2=(22/0.4)=(220/4)=55

Q. Find the average molar mass of a gaseous mixture in $g / m o l e,$ which contains $1.2046 \times 1 0^{23}$ atoms of an unknown gas and 0.2 mole of $H$ , gas. The weight of mixture is 22 g.

44

55

110

22

Average molar mass $= \frac{Total weight}{Total moles}$

$\frac{22}{\frac{1.2046 \times 1 0 ^{23}}{6.023 \times 1 0 ^{23}}} + 0.2 = \frac{22}{0.4} = \frac{220}{4} = 55$

Q. Find the average molar mass of a gaseous mixture in g/mole, which contains 1.2046×1023 atoms of an unknown gas and 0.2 mole of H, gas. The weight of mixture is 22 g.

44

55

110

22

Average molar mass = Total moles Total weight ​ 6.023×10231.2046×1023​22​+0.2=0.422​=4220​=55

Q. Find the average molar mass of a gaseous mixture in $g / m o l e,$ which contains $1.2046 \times 1 0^{23}$ atoms of an unknown gas and 0.2 mole of $H$ , gas. The weight of mixture is 22 g.

Average molar mass $= \frac{Total weight}{Total moles}$

$\frac{22}{\frac{1.2046 \times 1 0 ^{23}}{6.023 \times 1 0 ^{23}}} + 0.2 = \frac{22}{0.4} = \frac{220}{4} = 55$