Find the area of square inscribed in a circle x2+y2-6x-8y=0 .

Question

Find the area of square inscribed in a circle x2+y2-6x-8y=0 . (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/m-fsmrxkjwn4ov3qgb.jpg" /> Circle x2+y2-6x-8y=0 r=√9 + 16=5 diameter =10 (1/2) (diagonal Area =(1/2)(10=50 Sq. units.

Q. Find the area of square inscribed in a circle $x^{2} + y^{2} - 6 x - 8 y = 0$ .

Circle $x^{2} + y^{2} - 6 x - 8 y = 0$
$r = 9 + 16 = 5$
diameter $= 10$
$\frac{1}{2}$ (diagonal
Area $= \frac{1}{2} (10 = 50$ Sq. units.

Q. Find the area of square inscribed in a circle x2+y2−6x−8y=0 .

Circle x2+y2−6x−8y=0 r=9+16​=5 diameter =10 21​ (diagonal Area =21​(10=50 Sq. units.

Q. Find the area of square inscribed in a circle $x^{2} + y^{2} - 6 x - 8 y = 0$ .

Circle $x^{2} + y^{2} - 6 x - 8 y = 0$
$r = 9 + 16 = 5$
diameter $= 10$
$\frac{1}{2}$ (diagonal
Area $= \frac{1}{2} (10 = 50$ Sq. units.