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Q. Find the area of square inscribed in a circle $x^{2}+y^{2}-6x-8y=0$ .

NTA AbhyasNTA Abhyas 2022

Solution:

Solution
Circle $x^{2}+y^{2}-6x-8y=0$
$r=\sqrt{9 + 16}=5$
diameter $=10$
$\frac{1}{2}$ (diagonal
Area $=\frac{1}{2}(10=50$ Sq. units.