Figure shows two ships moving in x-y plane with velocities VA and VB. The ships move such that B always remains north of A. The ratio (V text A /VB) is equal to

Question

Figure shows two ships moving in x-y plane with velocities VA and VB. The ships move such that B always remains north of A. The ratio (V text A /VB) is equal to (A)  cos θ (B)  sin θ (C)  sec θ (D)  textcosec θ

Tardigrade Admin · Accepted Answer

If ship B is always north of ship A then, their horizontal component should be equal, so, VA=VB cos θ ⇒ (VA/VB)= cos θ

Q. Figure shows two ships moving in $x - y$ plane with velocities $V_{A}$ and $V_{B}$ . The ships move such that $B$ always remains north of $A$ . The ratio $\frac{V _{A}}{V _{B}}$ is equal to

$cos θ$

$sin θ$

$sec θ$

$cosec θ$

If ship $B$ is always north of ship $A$ then, their horizontal component should be equal, so,
$V_{A} = V_{B} cos θ$
$\Rightarrow \frac{V _{A}}{V _{B}} = cos θ$

Q. Figure shows two ships moving in x−y plane with velocities VA​ and VB​. The ships move such that B always remains north of A. The ratio VB​VA ​​ is equal to

cosθ

sinθ

secθ

cosecθ