Question

Figure shows two ships moving in $x-y$ plane with velocities $V_{A}$ and $V_{B}$. The ships move such that $B$ always remains north of $A$. The ratio $\frac{V_{\text {A }}}{V_{B}}$ is equal to

• A. $\cos \theta$
• B. $\sin \theta$
• C. $\sec \theta$
• D. $\text{cosec} \theta$

Answer 1

Answer: (A)

If ship $B$ is always north of ship $A$ then, their horizontal component should be equal, so,
$V_{A}=V_{B} \cos \theta$
$\Rightarrow \frac{V_{A}}{V_{B}}=\cos \theta$