Figure shows two holes in a wide tank containing a liquid common. The water streams coming out of these holes strike the ground at the same point. What is the height of liquid column in the tank?

Question

Figure shows two holes in a wide tank containing a liquid common. The water streams coming out of these holes strike the ground at the same point. What is the height of liquid column in the tank? <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/e78c41be54ad2a32b3fc39e0da0db319-.png" /> (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Range R = 2√h(H -h) R1 = R2 ⇒ 2√h1(H -h1) = 2√h2(H -h2) 4(H -4)= 6(H -6) or 2H =36 -16 =20 or H =10 cm

Q. Figure shows two holes in a wide tank containing a liquid common. The water streams coming out of these holes strike the ground at the same point. What is the height of liquid column in the tank?

Range $R = 2 h (H - h)$
$R_{1} = R_{2} \Rightarrow 2 h_{1} (H - h_{1}) = 2 h_{2} (H - h_{2})$
$4 (H - 4) = 6 (H - 6)$
or $2 H = 36 - 16 = 20$ or $H = 10 c m$

Q. Figure shows two holes in a wide tank containing a liquid common. The water streams coming out of these holes strike the ground at the same point. What is the height of liquid column in the tank?

Range R=2h(H−h)​ R1​=R2​⇒2h1​(H−h1​)​=2h2​(H−h2​)​ 4(H−4)=6(H−6) or 2H=36−16=20 or H=10cm

Range $R = 2 h (H - h)$
$R_{1} = R_{2} \Rightarrow 2 h_{1} (H - h_{1}) = 2 h_{2} (H - h_{2})$
$4 (H - 4) = 6 (H - 6)$
or $2 H = 36 - 16 = 20$ or $H = 10 c m$