Figure shows two blocks connected by a light inextensible string as shown in figure. A force of 10 N is applied on the bigger block at 60° with horizontal, then the tension in the string connecting the two masses is

Question

Figure shows two blocks connected by a light inextensible string as shown in figure. A force of 10 N is applied on the bigger block at 60° with horizontal, then the tension in the string connecting the two masses is (A) 5 N (B) 2 N (C) 1 N (D) 3 N

Tardigrade Admin · Accepted Answer

F text net =M a (10 cos 60°)=(3+2) a a=1 m / s 2 T=2(1)=2 N

Q. Figure shows two blocks connected by a light inextensible string as shown in figure. A force of $10 N$ is applied on the bigger block at $6 0^{\circ}$ with horizontal, then the tension in the string connecting the two masses is

5 N

2 N

1 N

3 N

$F_{net} = M a$
$(10 cos 6 0^{\circ}) = (3 + 2) a$
$a = 1 m / s^{2}$
$T = 2 (1) = 2 N$

Q. Figure shows two blocks connected by a light inextensible string as shown in figure. A force of 10N is applied on the bigger block at 60∘ with horizontal, then the tension in the string connecting the two masses is

5 N

2 N

1 N

3 N

Fnet ​=Ma (10cos60∘)=(3+2)a a=1m/s2 T=2(1)=2N

Q. Figure shows two blocks connected by a light inextensible string as shown in figure. A force of $10 N$ is applied on the bigger block at $6 0^{\circ}$ with horizontal, then the tension in the string connecting the two masses is

$F_{net} = M a$
$(10 cos 6 0^{\circ}) = (3 + 2) a$
$a = 1 m / s^{2}$
$T = 2 (1) = 2 N$