Q.
Figure shows two blocks connected by a light inextensible string as shown in figure. A force of $10\, N$ is applied on the bigger block at $60^{\circ}$ with horizontal, then the tension in the string connecting the two masses is
Laws of Motion
Solution:
$F_{\text {net }}=M a$
$\left(10 \cos 60^{\circ}\right)=(3+2) a$
$a=1\, m / s ^{2}$
$T=2(1)=2\, N$
