Figure shows the variation of electric field intensity E versus distanc x. What is the potential difference between the points at x=2 m and at x=6 m from O ?

Question

Figure shows the variation of electric field intensity E versus distanc x. What is the potential difference between the points at x=2 m and at x=6 m from O ? (A) 30 V (B) 60 V (C) 40 V (D) 80 V

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/6a777e92d8c6c34d3d6b5c64044ed04e-.png" /> V2-V6=-∫ E d r V2-V6=(10)(2)+(1/2)(10)(2)=30

Q. Figure shows the variation of electric field intensity $E$ versus distanc $x$ . What is the potential difference between the points at $x = 2 m$ and at $x = 6 m$ from $O ?$

30 V

60 V

40 V

80 V

$V_{2} - V_{6} = - \int E d r$
$V_{2} - V_{6} = (10) (2) + \frac{1}{2} (10) (2) = 30$

Q. Figure shows the variation of electric field intensity E versus distanc x. What is the potential difference between the points at x=2m and at x=6m from O?