Question

Figure shows the variation of electric field intensity $E$ versus distanc $x$. What is the potential difference between the points at $x=2 \,m$ and at $x=6 \,m$ from $O ?$

• A. 30 V
• B. 60 V
• C. 40 V
• D. 80 V

Answer 1

Answer: (A)

$V_{2}-V_{6}=-\int E d r$
$V_{2}-V_{6}=(10)(2)+\frac{1}{2}(10)(2)=30$