Figure shows a set of equipotential surfaces. The magnitude and direction of electric field that exists in the region is

Question

Figure shows a set of equipotential surfaces. The magnitude and direction of electric field that exists in the region is (A) 10 √2 V / m at 45° with x-axis (B) 10 √2 V / m at -45° with x-axis (C) 5 √2 V / m at 45° with x-axis (D) 5 √2 V / m at -45° with x-axis

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/10ae5b1398d1ee39d28c68adf24b3fec-.png" /> E=(10 √2/1) E=10 √2 at 45° with x-axis

Q. Figure shows a set of equipotential surfaces. The magnitude and direction of electric field that exists in the region is

$102 V / m$ at $4 5^{\circ}$ with $x$ -axis

$102 V / m$ at $- 4 5^{\circ}$ with $x$ -axis

$52 V / m$ at $4 5^{\circ}$ with $x$ -axis

$52 V / m$ at $- 4 5^{\circ}$ with $x$ -axis

$E = \frac{10 2}{1}$
$E = 102$ at $4 5^{\circ}$ with $x$ -axis

Q. Figure shows a set of equipotential surfaces. The magnitude and direction of electric field that exists in the region is

102​V/m at 45∘ with x-axis

102​V/m at −45∘ with x-axis

52​V/m at 45∘ with x-axis

52​V/m at −45∘ with x-axis

E=1102​​ E=102​ at 45∘ with x-axis

$102 V / m$ at $4 5^{\circ}$ with $x$ -axis

$102 V / m$ at $- 4 5^{\circ}$ with $x$ -axis

$52 V / m$ at $4 5^{\circ}$ with $x$ -axis

$52 V / m$ at $- 4 5^{\circ}$ with $x$ -axis

$E = \frac{10 2}{1}$
$E = 102$ at $4 5^{\circ}$ with $x$ -axis