Question

Figure shows a set of equipotential surfaces. The magnitude and direction of electric field that exists in the region is

• A. $10 \sqrt{2}\, V / m$ at $45^{\circ}$ with $x$-axis
• B. $10 \sqrt{2} \,V / m$ at $-45^{\circ}$ with $x$-axis
• C. $5 \sqrt{2} \,V / m$ at $45^{\circ}$ with $x$-axis
• D. $5 \sqrt{2}\, V / m$ at $-45^{\circ}$ with $x$-axis

Answer 1

Answer: (A)

$E=\frac{10 \sqrt{2}}{1}$
$E=10 \sqrt{2}$ at $45^{\circ}$ with $x$-axis