Figure represents the position-time graph of a body of mass 4 kg . Impulse (kg ms-1) imparted to the body at t = 0 is

Question

Figure represents the position-time graph of a body of mass 4 kg . Impulse (kg ms-1) imparted to the body at t = 0 is <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/2badaf1f314bb78dd543402ed5694ed9-.png" /> (A) 6 (B) 4 (C) 3 (D) 0

Tardigrade Admin · Accepted Answer

Since, we know that from a position-time graph of a body
Velocity of the body,

V

= slope of position-time graph
From the graph,

V = \frac{Δ x}{Δ t} = \frac{3}{2}

= \frac{3}{2} m / s

Since, we know that
Impulse = Change in linear momentum

= m . V

= 4 \times \frac{3}{2} = 6 K g - m s^{- 1}

Q. Figure represents the position-time graph of a body of mass 4kg . Impulse (kgms−1) imparted to the body at t=0 is

6

4

3

0

Since, we know that from a position-time graph of a body Velocity of the body, V= slope of position-time graph From the graph, V=ΔtΔx​=23​ =23​m/s Since, we know that Impulse = Change in linear momentum =m.V =4×23​=6Kg−ms−1

Q. Figure represents the position-time graph of a body of mass $4 k g$ . Impulse $(k g m s^{- 1})$ imparted to the body at $t = 0$ is