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Q. Figure represents the position-time graph of a body of mass $ 4 \,kg $ . Impulse $ (kg\, ms^{-1}) $ imparted to the body at $ t = 0 $ is
image

AMUAMU 2018Laws of Motion

Solution:

Since, we know that from a position-time graph of a body
Velocity of the body, $V$= slope of position-time graph
From the graph,
$V=\frac{\Delta \, x} {\Delta\,t}=\frac{3}{2}$
$=\frac{3}{2}\, m/s$
Since, we know that
Impulse = Change in linear momentum
$=m.V$
$=4 \times \frac{3}{2}=6\,Kg-ms^{-1}$