figure below shows two paths that may be taken by a gas to go from a state A to a state C. In process AB, 400 J of heat is added to the system and in process BC, 100 J of heat is added to the system. The heat absorbed by the system in the process AC will be:

Question

figure below shows two paths that may be taken by a gas to go from a state A to a state C. In process AB, 400 J of heat is added to the system and in process BC, 100 J of heat is added to the system. The heat absorbed by the system in the process AC will be: (A) 460 J (B) 300 J (C) 380 J (D) 500 J

Tardigrade Admin · Accepted Answer

In cyclic process ABCA, Δ Ucyclic = 0 Qcyclic = Wcyclic QAB = Qbc + QCA = closed loop area. 400 + 100+ QCA = (1/2)× (2× 10-3) × 4× 104 400 +100 QAC = 40 QAC = 460 J

Q. figure below shows two paths that may be taken by a gas to go from a state A to a state C.
In process AB, 400 J of heat is added to the system and in process BC, 100 J of heat is added to the system. The heat absorbed by the system in the process AC will be:

460 J

300 J

380 J

500 J

In cyclic process ABCA,
$Δ U X_{cyclic} = 0$
$Q X_{cyclic} = W X_{cyclic}$
$Q X_{AB} = Q X_{bc} + Q X_{CA} =$ closed loop area.
$400 + 100 + Q_{C A} = \frac{1}{2} \times (2 \times 1 0^{- 3}) \times 4 \times 1 0^{4}$
$400 + 100 Q X_{AC = 40}$
$Q X_{AC} = 460 J$

Q. figure below shows two paths that may be taken by a gas to go from a state A to a state C. In process AB, 400 J of heat is added to the system and in process BC, 100 J of heat is added to the system. The heat absorbed by the system in the process AC will be: