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Q. figure below shows two paths that may be taken by a gas to go from a state A to a state C.
In process AB, 400 J of heat is added to the system and in process BC, 100 J of heat is added to the system. The heat absorbed by the system in the process AC will be:Physics Question Image

AIPMTAIPMT 2015

Solution:

In cyclic process ABCA,
$\Delta \ce{U_{cyclic}} = 0$
$\ce{Q_{cyclic} = W_{cyclic}}$
$\ce{Q_{AB} = Q_{bc} + Q_{CA} =}$ closed loop area.
$400 + 100+ Q_{CA} = \frac{1}{2}\times (2\times 10^{-3}) \times 4\times 10^4$
$\ce{400 +100 Q_{AC = 40}}$
$\ce{Q_{AC} = 460 J}$