Question

Figure below shows regular hexagon, the charges are placed at the vertices. In which of the following cases the electric field at the centre is zero?

• A.
• B.
• C.
• D.

Answer 1

Answer: (D)

The intensity of electric field $(E)$ due to charge $(q)$ placed at a distance $(r)$ is given by
$E=\frac{1}{4\pi {\epsilon }_0}\frac{q}{r}$

In Fig. II as is evident the electric field $(E)$ due to opposite charges cancel each other. The field due to charge at $B$ and $E$ are equal and opposite, hence cancel out, similarly due to $A$ and $D$, and due to $D$ and $C$. Therefore, resultant field is zero.