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Q.
Figure below shows regular hexagon, the charges are placed at the vertices. In which of the following cases the electric field at the centre is zero?
AMUAMU 2000
Solution:
The intensity of electric field $(E)$ due to charge $(q)$ placed at a distance $(r)$ is given by
$ E=\frac{1}{4\pi \varepsilon_{0}}\frac{q}{r} $
In Fig. II as is evident the electric field $(E)$ due to opposite charges cancel each other. The field due to charge at $B$ and $E$ are equal and opposite, hence cancel out, similarly due to $A$ and $D$, and due to $D$ and $C$. Therefore, resultant field is zero.
