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Question
Mathematics
f: R arrow R defined by f(x)= f(x) = begincases 2x ; x> 3 x2 ; 1 < x le 3 3x ; x le 1 endcases then f(-2)+f(3)+f(4) is
Q.
f
:
R
→
R
defined by
f
(
x
)
=
f
(
x
)
=
⎩
⎨
⎧
2
x
;
x
>
3
x
2
;
1
<
x
≤
3
3
x
;
x
≤
1
then
f
(
−
2
)
+
f
(
3
)
+
f
(
4
)
is
1532
144
KCET
KCET 2021
Relations and Functions
Report Error
A
14
0%
B
9
100%
C
5
0%
D
11
0%
Solution:
f
(
−
2
)
+
f
(
3
)
+
f
(
4
)
−
6
+
9
+
8
=
11