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  4. f: R arrow R defined by f(x)= f(x) = begincases 2x ; x> 3 x2 ; 1 < x le 3 3x ; x le 1 endcases then f(-2)+f(3)+f(4) is

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Q. f:R→R defined by f(x)= f(x)={2x;x>3x2;1<x≤33x;x≤1 then f(−2)+f(3)+f(4) is

KCETKCET 2021Relations and Functions

Solution:

f(−2)+f(3)+f(4)
−6+9+8
=11