Extremities of the latera recta of the ellipse (x2/a2)+(y2/b2)=1(ab) having a given major axis 2 a lies on

Question

Extremities of the latera recta of the ellipse (x2/a2)+(y2/b2)=1(a>b) having a given major axis 2 a lies on (A) x2=a(a-y) (B) x2=a(a+y) (C) y2=a(a+x). (D) y2=a(a-x)

Tardigrade Admin · Accepted Answer

Correct answer is (a) x2=a(a-y)Correct answer is (b) x2=a(a+y)

Q. Extremities of the latera recta of the ellipse $\frac{x ^{2}}{a ^{2}} + \frac{y ^{2}}{b ^{2}} = 1 (a > b)$ having a given major axis $2 a$ lies on

$x^{2} = a (a - y)$

$x^{2} = a (a + y)$

$y^{2} = a (a + x)$ .

$y^{2} = a (a - x)$

Correct answer is (a) $x^{2} = a (a - y)$ Correct answer is (b) $x^{2} = a (a + y)$

Q. Extremities of the latera recta of the ellipse a2x2​+b2y2​=1(a>b) having a given major axis 2a lies on

x2=a(a−y)

x2=a(a+y)

y2=a(a+x).

y2=a(a−x)