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  4. Extremities of the latera recta of the ellipse (x2/a2)+(y2/b2)=1(a>b) having a given major axis 2 a lies on

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Q. Extremities of the latera recta of the ellipse $\frac{x^2}{a^2}+\frac{y^2}{b^2}=1(a>b)$ having a given major axis $2 a$ lies on

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Solution:

Correct answer is (a) $x^2=a(a-y)$Correct answer is (b) $x^2=a(a+y)$