Expression for an electric field is given by vec E =4000 x2 i ( V / m ). The electric flux through the cube of side 20 when placed in electric field (as shown in the figure) is V cm.

Question

Expression for an electric field is given by vec E =4000 x2 i ( V / m ). The electric flux through the cube of side 20 when placed in electric field (as shown in the figure) is V cm. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Flux = vec E ⋅ vec A =4000(0 ⋅ 2)2 ( V / m ) ⋅(0 ⋅ 2)2 m 2 =4000 × 16 × 10-4 Vm =640 Vcm

Q. Expression for an electric field is given by $E = 4000 x^{2} i \frac{V}{m}$ . The electric flux through the cube of side $20$ when placed in electric field (as shown in the figure) is ___ $V c m$ .

Flux $= E \cdot A$
$= 4000 (0 \cdot 2)^{2} \frac{V}{m} \cdot (0 \cdot 2)^{2} m^{2}$
$= 4000 \times 16 \times 1 0^{- 4} Vm$
$= 640 V c m$

Q. Expression for an electric field is given by E=4000x2imV​. The electric flux through the cube of side 20 when placed in electric field (as shown in the figure) is ___Vcm.

Flux =E⋅A =4000(0⋅2)2mV​⋅(0⋅2)2m2 =4000×16×10−4Vm =640Vcm

Q. Expression for an electric field is given by $E = 4000 x^{2} i \frac{V}{m}$ . The electric flux through the cube of side $20$ when placed in electric field (as shown in the figure) is ___ $V c m$ .

Flux $= E \cdot A$
$= 4000 (0 \cdot 2)^{2} \frac{V}{m} \cdot (0 \cdot 2)^{2} m^{2}$
$= 4000 \times 16 \times 1 0^{- 4} Vm$
$= 640 V c m$