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Q. Expression for an electric field is given by $\vec{ E }=4000 x^2 i \frac{ V }{ m }$. The electric flux through the cube of side $20 \,$ when placed in electric field (as shown in the figure) is ___$V cm$.Physics Question Image

JEE MainJEE Main 2023Electric Charges and Fields

Solution:

Flux $ =\vec{ E } \cdot \vec{ A } $
$ =4000(0 \cdot 2)^2 \frac{ V }{ m } \cdot(0 \cdot 2)^2 m ^2$
$ =4000 \times 16 \times 10^{-4} Vm $
$ =640 \,Vcm $