Excited hydrogen atom emits light in the ultraviolet region at 2.47 × 1015 Hz. With this frequency, the energy of a single photon is: (h = 6.63 × 10-34 Js)

Question

Excited hydrogen atom emits light in the ultraviolet region at 2.47 × 1015 Hz. With this frequency, the energy of a single photon is: (h = 6.63 × 10-34 Js) (A) 8.041 × 10-40 J (B) 2.680 × 10-19 J (C) 1.640 × 10-18 J (D) 6.111 × 10-17 J

Tardigrade Admin · Accepted Answer

E=hv = 6.63×10-4×2.47×1015 =1.640×10-18 J

Q. Excited hydrogen atom emits light in the ultraviolet region at $2.47 \times 1 0^{15} Hz$ . With this frequency, the energy of a single photon is :
$(h = 6.63 \times 1 0^{- 34} J s)$

$8.041 \times 1 0^{- 40}$ J

$2.680 \times 1 0^{- 19}$ J

$1.640 \times 1 0^{- 18}$ J

$6.111 \times 1 0^{- 17}$ J

$E = h v$

$= 6.63 \times 1 0^{- 4} \times 2.47 \times 1 0^{15}$

$= 1.640 \times 1 0^{- 18} J$

Q. Excited hydrogen atom emits light in the ultraviolet region at 2.47×1015Hz. With this frequency, the energy of a single photon is : (h=6.63×10−34Js)

8.041×10−40 J

2.680×10−19 J

1.640×10−18 J

6.111×10−17 J