Question

Excited hydrogen atom emits light in the ultraviolet region at $2.47 \times 10^{15}\, Hz$. With this frequency, the energy of a single photon is :
$(h = 6.63 \times 10^{-34}\, Js)$

• A. $8.041 \times 10^{-40}$ J
• B. $2.680 \times 10^{-19}$ J
• C. $1.640 \times 10^{-18}$ J
• D. $6.111 \times 10^{-17}$ J

Answer 1

Answer: (C)

$E=hv$

$= 6.63\times10^{-4}\times2.47\times10^{15}$

$=1.640\times10^{-18}\,J$