Evaluate how much amount of calcium oxide would be required when it reacts with 852 g of P4O10 .

Question

Evaluate how much amount of calcium oxide would be required when it reacts with 852 g of P4O10 . (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

6 CaO + P 4 O 10 arrow 2 Ca 3 PO 42 1 Mole P 4 O 10=284 g / mole Moles of P 4 O 10=(852/284)=3 moles Moles of CaO =18 moles Mass of CaO =18 × 56=1008 g

Q. Evaluate how much amount of calcium oxide would be required when it reacts with $852 g$ of $P_{4} O_{10}$ .

$6 C a O + P_{4} O_{10} \to 2 C a_{3} P O_{42}$
$1$ Mole $P_{4} O_{10} = 284 g / m o l e$
Moles of $P_{4} O_{10} = \frac{852}{284} = 3$ moles
Moles of $C a O = 18$ moles
Mass of $C a O = 18 \times 56 = 1008 g$

Q. Evaluate how much amount of calcium oxide would be required when it reacts with 852g of P4​O10​ .

6CaO+P4​O10​→2Ca3​PO42​ 1 Mole P4​O10​=284g/mole Moles of P4​O10​=284852​=3 moles Moles of CaO=18 moles Mass of CaO=18×56=1008g

Q. Evaluate how much amount of calcium oxide would be required when it reacts with $852 g$ of $P_{4} O_{10}$ .

$6 C a O + P_{4} O_{10} \to 2 C a_{3} P O_{42}$
$1$ Mole $P_{4} O_{10} = 284 g / m o l e$
Moles of $P_{4} O_{10} = \frac{852}{284} = 3$ moles
Moles of $C a O = 18$ moles
Mass of $C a O = 18 \times 56 = 1008 g$