Thank you for reporting, we will resolve it shortly
Q.
Evaluate how much amount of calcium oxide would be required when it reacts with $852 \,g$ of $P_{4}O_{10}$ .
NTA AbhyasNTA Abhyas 2022
Solution:
$6 CaO + P _4 O _{10} \rightarrow 2 Ca _3 PO _{42}$
$1$ Mole $P _4 O _{10}=284\, g / mole$
Moles of $P _4 O _{10}=\frac{852}{284}=3$ moles
Moles of $CaO =18$ moles
Mass of $CaO =18 \times 56=1008 \,g$