Question

Equation of the straight line which meets the circle $x^2+y^2=8$ at two points where these points are at a distance of $2$ units from the point $A\left(2,2\right)$ is

• A. $x+y=2$
• B. $x+y=3$
• C. $x+y=1$
• D. $x+y=0$

Answer 1

Answer: (B)

Equation of circle assuming $A\left(2,2\right)$ as
centre and radius equal to $2$ units is ${\left(x-2\right)}^2+{\left(y-2\right)}^2=2^2$ … $\left(1\right)$
equation of given circle is $x^2+y^2=8$ … $\left(2\right)$
equation $\left(2\right)$ $-$ equation $\left(1\right)$ gives
$4x+4y-8=4$ $\Rightarrow x+y=3$
which is the required equation